Note that one food calorie is not the same as a thermodynamic calorie, and that 1 cal/(cc deltaC) is just "shv_water".
1 foodcal - (12 floz * (1 cal/(cc deltaC)) * (98-32) deltaF) ? foodcal = -12.0124 foodcalCould they make it taste better with 13 calories and call it 0?
Note: dens_helium is not in WWW version database, neither is the volume of a balloon
so we will define them as new units...
Note: You can only define new units in the Windows version of Calchemy.
dens_helium = 4.0026 gram/mole; volumetric_gas_const balloon = (4/3) pi (6 inch)^3 (dens_air - dens_helium); 5 pounds ? balloons = 137.284 balloons
1 inch/hour; pi (3 inch)^2; 0.2 cc/drop ? seconds/drop = 1.55396 seconds/drop
Assume the lamp burns 12 hours on one quart of kerosene.
1 qt; hcv_kerosene; 12 hours ? watt = 826.703 wattGood for reading by on a cold winters night :-)
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Last Updated 6/21/2009