Measure how long it takes the car to slow from 60 mph to 55 mph "coasting" Kinetic energy (1/2 m v^2) converted to heat (energy consumed in "n" sec)
(1/2) (3720 lbm * ((60 mph)^2 - (55 mph)^2)) / (7 sec) ? hp = 18.5728 hpWhat is the efficiency of the engine if the car gets 30 mpg?
18.5728 hp; hcv_gasoline; 60 mph; 30 miles/gal ? % = 20.3655 % = 491.026 %Why are there two answers?
What is the flow rate of gas in the gas line?
60 mph; 30 mile/gal ? cc/sec = 2.10301 cc/sec
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Last Updated 6/21/2009